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Diagram · CC BY 4.0

Z-score example: comparing SAT and ACT scores

Two students on different tests: SAT 1800 is z = 1 (84.13%); ACT 24 is z = 0.6 (72.57%).

The z-score of Student A: an SAT score of 1800, where SAT scores have mean 1500 and standard deviation 300, so z = (1800 − 1500) / 300 = 1. The area under the normal curve to the left of z is shaded: 0.8413, so under the normal model 84.13% of test-takers scored lower. The horizontal axis carries two scales, the z-score from −3 to +3 and the SAT score (600, 900, 1200, 1500, 1800, 2100, 2400; the pre-2016 SAT scale). An orange line marks the student's score. A key names the shading.

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Z-score of Student A (SAT 1800) on the normal curve. Derek Jansen, Grad Coach, CC BY 4.0.

Student B: an ACT score of 24

The second half of the example: z = (24 − 21) / 5 = 0.6, with 72.57% of test-takers below under the normal model.

The z-score of Student B: an ACT score of 24, where ACT scores have mean 21 and standard deviation 5, so z = (24 − 21) / 5 = 0.6. The area under the normal curve to the left of z is shaded: 0.7257, so under the normal model 72.57% of test-takers scored lower. The horizontal axis carries two scales, the z-score from −3 to +3 and the ACT score (6, 11, 16, 21, 26, 31, 36). An orange line marks the student's score. A key names the shading.

Swipe sideways to see the whole diagram, or download the PNG.

Z-score of Student B (ACT 24) on the normal curve. Derek Jansen, Grad Coach, CC BY 4.0.

"Z-score of Student B (ACT 24) on the normal curve" by Derek Jansen, Grad Coach (https://gradcoach.com/open-educational-resources/z-score-example/) is licensed under CC BY 4.0 (https://creativecommons.org/licenses/by/4.0/).

Cite it (APA 7):Jansen, D. (2026). Z-score of Student B (ACT 24) on the normal curve [Diagram]. Figshare. https://doi.org/10.6084/m9.figshare.34792317

What it shows

Two diagrams for one worked example. Student A scored 1800 on the SAT and Student B scored 24 on the ACT; converting each score to a z-score puts them on the same scale, so they can be compared.

On each normal curve the area to the left of the student’s score is shaded: under the normal model, the share of test-takers who scored lower. Each axis carries the z-score and the test’s own scale.

How to read it

  1. Subtract the mean, then divide by the standard deviation. For Student A, z = (1800 − 1500) / 300 = 1.

  2. For Student B, z = (24 − 21) / 5 = 0.6.

  3. The shaded areas give the share of test-takers below each student under the normal model: 0.8413 (84.13%) for Student A and 0.7257 (72.57%) for Student B.

  4. Student A sits further above the mean in standard-deviation terms, so Student A’s score is the stronger result relative to other test-takers.

The numbers behind it

  • SAT (Student A): mean 1500, standard deviation 300, score 1800, z = 1, area to the left 0.8413 (84.13%).
  • ACT (Student B): mean 21, standard deviation 5, score 24, z = 0.6, area to the left 0.7257 (72.57%).
  • The SAT axis uses the pre-2016 scale, from 600 to 2400; the ACT axis runs from 6 to 36.

Ways to use it in teaching

  • Before showing the curves, ask which student did better; the raw scores alone cannot answer it.

  • Have students add a third student on another test, with its own mean and standard deviation, and place them on the same scale.

  • Note that the percentiles rely on the normal model, which real score distributions only approximate.

For the summary statistics behind this kind of chart, see our plain-language guide to descriptive statistics.

Sources

  • Diez, D. M., Barr, C. D., & Çetinkaya-Rundel, M. (2012). OpenIntro statistics (2nd ed.). OpenIntro.
  • Standard score. (n.d.). In Wikipedia. Retrieved October 18, 2026, from https://en.wikipedia.org/wiki/Standard_score

Inference and evidence

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